
Jacob C. answered 05/28/21
Adaptive Math and Physics Tutor
I'll show the case when h(x) = f o g(x) = f(g(x)).
c1 = h(1) = f(g(1)) = f(2) = 3
c2 = h(2) = f(g(2)) = f(3) = 1
c3 = h(3) = f(g(3)) = f(3) = 1
c4 = h(4) = f(g(4)) = f(3) = 1
The definition of g shows that g(1) = 2, g(2) = 3, g(3) = 3, and g(4) = 3. Those are the substitutions that I made above, and I then used the definition of f to determine f(g(x)).
Thus, when h(x) = f o g(x), h is the function {(1, 3), (2, 1), (3, 1), (4, 1)}.
Using this same procedure, you should be able to figure out the values of c for the other cases given.