Inactive Tutor answered 05/23/21
Number of throws until 1 success is a geometric distribution
p = 0.739
The variance is (1-p)/p2
so the standard deviation is [√ (1-p)] / p = 0.6913
the mean is 1/p = 1.353
Daniel K.
asked 05/23/21what is the standard deviation of the number of dart throws I have to make until I get a bulls-eye (assuming my chances of making a bulls-eye on any throw is 0.739).
Inactive Tutor answered 05/23/21
Number of throws until 1 success is a geometric distribution
p = 0.739
The variance is (1-p)/p2
so the standard deviation is [√ (1-p)] / p = 0.6913
the mean is 1/p = 1.353
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