parabola question help

Question

y = -0.33x^2 + 0.84x + 6

substitute x = 3 into the equation of the parabola, find the coordinates of the point where the line x= 3 meets the parabola?

Answer 1

y=-.33x^2 +.84x + 6

f(3)=-.33(3)^2 + .84(3) + 6 = -2.97 + 2.52 + 6 = 5.55

(3, 5.55) is the point where the line x=3 intersects the parabola

It's a downward opening parabola, with only one intersection point with a vertical line.