Chemistry question

Question

How many moles of sodium sulfate are formed when 13.2 moles of sulfuric acid reacts with 30.6 moles of sodium hydroxide? Which reactant is limiting? How many moles of the excess reactant will be left after the reaction? H2SO4+ 2NaOH --> Na2SO4+2H2O

Answer 1

Limiting reactant:

13.2 mol H₂SO₄ (mol Na₂SO₄ / 1 mol H₂SO₄) = 13.2 mol Na₂SO₄ (142.04g / mol) = 1874g Na₂SO₄

30.6 mol NaOH (mol Na₂SO₄ / 2 mol NaOH) = 15.3 mol Na₂SO₄ (142.04g / mol) = 2173g Na₂SO₄

Excess reactant:

13.2 mol Na₂SO₄ (2 mol NaOH / 1 mol Na₂SO₄) = 26.4 mol NaOH (consumed)

Total ER − total ER consumed

(30.6 mol NaOH) − (26.4 mol NaOH) = 4.2 mol NaOH

Answers:

How many moles of sodium sulfate are formed when 13.2 moles of sulfuric acid reacts with 30.6 moles of sodium hydroxide?

13.2 mol Na₂SO₄

Which reactant is limiting?

Sulfuric acid

How many moles of the excess reactant will be left after the reaction?

4.2 mol NaOH