Raymond B. answered 05/16/21
Math, microeconomics or criminal justice
slightly less than 2 1/4 meters = width of the border
Area of the rug = 100pi
Area of the border = 50pi
Area of both = 150pi = pi(r)^2 where r = radius of the enclosed area, rug+border
150pi = pi(r)^2 the pi's cancel leaving
150 = r^2
r = sqr150 = about 12.25
12.25-10 = 2.25 meters = width of the border