
John M. answered 05/11/21
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6sin^2 theta +7cos theta -8 =0
6Sin2θ + 7Cosθ - 8 = 0
You can substitute 1-Cos2θ for Sin2θ and get 6Cos2θ -7Cosθ +2 = 0
I graphed a solution and θ = 60° or 311.81°