Brittany A.

asked • 11/15/12# I need help trying to sole tan^2 x =1 where x is more than or equal to 0 but x is less than or equal to pi

this is what it looks like tan^2 x=1 where 0 ≤ x ≤ π

## 3 Answers By Expert Tutors

Emma D. answered • 11/15/12

Online Mech/Civil Engineering Tutor (MIT Alum, EIT, 10+ yr exp)

Hi Brittany,

The only numbers that square to one are 1 and -1.

1 = 1 x 1

1 = (-1) x (-1)

So since (tan x) squares to one, (tan x) must be 1 or -1. There are two values of x in the interval [0, pi] that make it happen.

tan (pi/4) = 1

tan (3*pi/4) = -1

Michael B.

Nice.

11/15/12

Robert J. answered • 11/15/12

Certified High School AP Calculus and Physics Teacher

Solve for tan x first, tan x = ±1

Therefore, x = pi/4, 3pi/4 on [0, pi]

Tamara J. answered • 11/15/12

Math Tutoring - Algebra and Calculus (all levels)

tan^{2}(x) = 1 , 0 ≤ x ≤ Π

tan^{2}(x) = 1 ==> (tan(x))^{2} = 1

√(tan(x))^{2 }= √1 ==> tan(x) = ± 1

Note the following: tan(x) = sin(x)/cos(x)

So, tan(x) = ± 1 ==> sin(x)/cos(x) = ± 1

Multiply both sides of the equation by cos(x):

(cos(x))·(sin(x)/cos(x)) = (cos(x))·(± 1)

sin(x) = ± cos(x)

Looking at the top half of a unit circle (where x is between 0 and Π)...

...find the coordinates where sin(x) = cos(x) and sin(x) = -cos(x)

You will see that the coordinates that match are (√2/2, √2/2), which is located at x = ∏/4, and (-√2/2, √2/2), which is located at x = 3Π/4.

Thus, x = Π/4 and x = 3Π/4

Elena B.

Excellent explanation!

11/18/12

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Brittany A.

thanks

11/15/12