From the 220 graduating students in a school, 110 attended semi - formal

Question

From the 220 graduating students in a school, 110 attended semi - formal and 150 attended the prom. If 58 students attended both events, how many students did not attend any event ?

Is this the answer?

We know that,

n(total) = 220

n(semi-formal) = 110

n(formal) = 150

n(both) = 58

Answer 1

The numbers accurately reflect the data, yet you do not answer the question: How many students did not attend any event?

Did you make a Venn Diagram?

If 58 attended both events, then 52 went only to the formal and 92 went only to the prom.

Add those and subtract from 220

Toe answer these problems you must become adapt at drawing and labeling Venn Diagrams!

Answer 2

TOTAL GRADUATING STUDENTS = 220

ATTENDED SEMI-FORMAL DANCE = 110

ATTENDED FORMAL PROM = 150

ATTENDED BOTH EVENTS = 58

NUMBER OF STUDENTS IN ATTENDANCE AT BOTH EVENTS COMBINED = 110 + 150 = 260OF THE

HOWEVER, 58 STUDENTS ATTENDED BOTH, SO IN ORDER TO NOT COUNT THE SAME STUDENT TWICE, WE WILL SUBTRACT THAT AMOUNT (58) FROM THE 260

260 - 58 = 202 OF THE GRADUATING STUDENTS ATTENDED THE DANCES

SO IF 202 OF THE GRADUATING SENIOR ATTENDED A DANCE, THEN...

220 - 202 = 18 OF THE GRADUATING STUDENTS DID NOT ATTEND A DANCE EVENT