Four ATV tires were sitting in a garage and then later moved outside on the snow. The tires in the garage had a pressure of 0.613 atm, a volume of 185.19 L, and a temperature of 50.0°C.

Question

 The tires in the snow outside have a temperature of -20.0°C and a volume of 180 L. What would be the new pressure in one of the tires lying on the snow?

Answer 1

Inside garage:

PV = nRT

(0.613) (185.19) = n (0.082) (323.15)

113.52 = n (26.50)

113.52 / 26.50 = n

4.28 = n

Outside garage:

PV = nRT

P (180) = 4.28(0.082)(253.15)

P (180) = 88.85

P = 88.85 / 180

P = 0.494 atm

Answer:

The new pressure in one of the tires lying on the snow would be 0.49 atm.