What is the density (g/L) of 5.0 moles of NH3, at 1.18 atm and 25.0oC?

Answer 1

Density = mass/volume

FINDING MASS:

Molar mass of NH₃ = 3(1.008 g) + 14.01 g = 17.034 g per 1 mole NH₃

5.0 mol NH₃ x 17.034 g NH₃/1 mol NH₃ = 85.17 g

FINDING VOLUME:

PV=nRT

(1.18 atm)V = (5.0 mol)(0.08206 L·atm/mol·K)(273 + 25.0 K)

V = 103.6 L

PLUG INTO DENSITY FORMULA:

Density = mass/volume

Density = 85.17 g / 103.6 L

Density = 0.82 g/L