J.R. S. answered 05/07/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
q = mC∆T
q = heat = ?
m = mass = 435 g
C = specific heat = 0.450 J/gº
∆T = change in temperature = 180º - 43º = 137º
q = (435 g)(0.450 J/gº)(137º)
q = 26,818 J = 26.8 kJ (3 sig, figs.)