Yes, you are right on the first part.

(b) Since K is fixed, you don't have to include K in your arrangement. There are 9 letters you need to arrange including 2 B's, 2 A's and 2 L's

(9!)/(2!2!2!) = 45360

(c) Since one B is fixed, you don't have to include one B in your arrangement. That means there are 9 letters you need to arrange including 2 A's and 2 L's

(9!)/(2!2!) = 90720

(d)This case is a little different. You can have 9 formats like this:

LL_ _ _ _ _ _ _ _

_LL_ _ _ _ _ _ _

_ _LL_ _ _ _ _ _

_ _ _LL _ _ _ _ _

_ _ _ _LL _ _ _ _

_ _ _ _ _LL _ _ _

_ _ _ _ _ _LL _ _

_ _ _ _ _ _ _LL _

_ _ _ _ _ _ _ _LL

What you need to do is to get the permutation of one format (like we did in b and c) then, we multiply by 9.

8!/(2!2!) * 9 = 90720