Hola please understand that I have needed help with my homework for weeks please someone actually respond and help me

Question

1.) For the reaction C + 2H2 → CH4, how many grams of hydrogen are required to produce 17 moles of methane, CH4 ?

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:

Element	Molar Mass
Hydrogen	1
Carbon	12

2.) 3 Cu + 8HNO3 → 3 Cu(NO3)2   + 2 NO + 4 H2O

In the above equation, how many grams of water can be made when 1.4 moles of HNO3 are consumed?

 

Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0

Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:



Element	Molar Mass
Hydrogen	1
Nitrogen	14
Copper	63.5
Oxygen	16

please help me by explaining and solving please

Answer 1

Hello, Ethan,

1.) For the reaction C + 2H2 → CH4, how many grams of hydrogen are required to produce 17 moles of methane, CH4 ?

The balanced equation tells us that it takes 2 moles of H₂ to make 1 mole of CH₄. That's a molar ratio of (2 hyrogen/1 methane) . Since we want 17 moles of methane, we'll need twice that number of moles of hydrogen, 34 moles. Multiply 34 moles H₂ time the molar mass of H₂ (2 grams/mole) to find that it will take 68 grams of hydrogen to produce 17 moles of methane.

2.) 3 Cu + 8HNO3 → 3 Cu(NO3)2   + 2 NO + 4 H2O

In the above equation, how many grams of water can be made when 1.4 moles of HNO3 are consumed?

Using the same logic, we see that the molar ratio of HNO₃,nitric acid, to water is 8/4. We make 4 moles of water for every 8 moles of nitric acid. So we should multiply the moles nitric acid by (1/2) to get moles H₂O. That means we only get 0.7 moles of water. Whoopee. Multiply moles water by it's molar mass to arrive at a water mass of 12.6 grams.

Bob

Answer 2

1) From the balanced reaction, 1 mole of CH₄ is formed for every 2 moles of H₂ that reacts. The mole ratio of H₂ to CH₄ is 2:1. Use this ratio to setup your stoichiometry conversion.

17 mol CH₄ x (2 mol H₂ / 1 mol CH₄) = 34 mol H₂

Convert mol H₂ of g of H₂ using its MW (2 g/mol).

34 mol H₂ x (2 g H₂ / 1 mol H₂) = 68 g H₂ ~ 68.0 g H₂ (rounded to the nearest tenth)

2) From the balanced reaction, 4 moles of H₂O is formed for every 8 moles of HNO₃ that reacts. The mole ratio of H₂O to HNO₃ is 4:8. Use this ratio to setup your stoichiometry conversion.

1.4 mol HNO₃ x (4 mol H₂O / 8 mol HNO₃) = 0.70 mol H₂O

Convert mol H₂O of g of H₂O using its MW (18 g/mol).

0.70 mol H₂O x (18 g H₂O / 1 mol H₂O) = 12.6 g H₂O (rounded to the nearest tenth)