Trent H. answered • 05/03/21
Applied Mathematics Student
c) Since 92! is cleanly divisible by 88!, you would be left with the factors that 92! has which 88! does not. The remaining problem left to solve is the product of 92, 91, 90, and 89.
d) Factorials represent the product of an integer and all integers below it. So really, you're problem is 5 x 4 x 3 x 2 x 1.
e) Now that we understand the definition of a factorial, this one is actually pretty simple, although it may look intimidating. If we have the product of (n+1) and all integers below it, and then we multiply (n+2) to that set, we we're really doing is creating the factorial of (n+2)!.
f) Again, we'll use the definition of factorials to figure this out. The numerator can expand to (n+1)(n)(n-1)!/(n-1)! Now we have a common factor, and are able to cancel out the (n-1)!s. What we are left with is (n+1)(n). The solution to this problem is the product of those two expressions.
Ally J.
Thank you so much for the help, so The answer for d) is 120? How about if it was like this 30x4!, the answer says it’s 6!, how do get that even though you know the answer is 720? I’m still confused with e) and f), for f) how is the numerator expand to that?05/03/21