Mixture Question

Question

Chris needs to mix a 30% acid solution with a 60% acid solution to create 100 millileters of a 36% solution. How many millileters of each solution must Chris use?

Answer 1

100 mL solution of 36% acid is what you want to create. You have 30% acid and 60% acid solutions. Your final solution is 36% of acid. In order to create this, you need x mL of 30% acid solution and y mL of 60% acid solution.

(x * (30/100)) + (y * (60/100)) = 100 * (36/100)

Simplifying this so it's more readable...

0.3x + 0.6y = 36

Additionally, you know that your final acid solution should be 100 mL in total.

x + y = 100

Using these equations, you can solve for x or y. I've solved for x below first.

0.3x +0.6 * (100-x) = 36

0.3x + 60 - 0.6x = 36

24 = 0.3x

x = 80

x + y =100

80 + y = 100

y = 20

That means you need 80 mL of the 30% acid solution and 20 mL of the 60% acid solution to make 100 mL of the 36% acid solution.