Find the equation of the hyperbola centered at the origin with a focus at (0,8) and a transverse axis of length 10.

Answer 1

Equation pf hyperbola y²/a² - x²/b² = 1; F(0,8) means c = 8; 2a = 10; a = 5; b² = c² - a² = 64 - 25 = 39;

y²/25 - x²/39 = 1 - equation of hyperbola