Mark M. answered 04/11/21
Retired math prof. Very extensive Precalculus tutoring experience.
The tangent function repeats every 180°.
So, tan 265° = tan(265° - 180°) = tan 85°
Ariel G.
asked 04/11/21Solve the following, where 0° < 𝜃 < 360°.
Find 𝜃 where tan𝜃 = tan265° and 𝜃 ≠ 265°.
What do I do after I found the reference angle of -95°?
please explain this whole question!
Mark M. answered 04/11/21
Retired math prof. Very extensive Precalculus tutoring experience.
The tangent function repeats every 180°.
So, tan 265° = tan(265° - 180°) = tan 85°
All trig functions are periodic, meaning they repeat. The tangent function repeats every 180°. So for a given value of θ, you'll get the same value of the tangent by adding or subtracting a multiple of 180° to θ; that is° θ ± n·180° where n = 1, 2, 3, ... So:
tan(265°) = tan(265° - 180°) = tan(265° + 180°), etc
But you need the one that lies between 0 and 360°.
Philip P.
04/11/21
Mark M. answered 04/11/21
Mathematics Teacher - NCLB Highly Qualified
Reference angle is 85°
tan 265° = tan 85°
Raymond B. answered 04/13/21
Math, microeconomics or criminal justice
theta = 85 degrees
tan85 = tan265. In 1st & 3rd quadrants tangents are always >0
tan85= about 11.43
cot85 = about 0.0875
sin85= about 0.996
cos85 = about 0.087
csc85 = 1/sin85 = about 1.004
sec85 = 1/cos85 = about 11.49
just use a calculator with trig functions. plug in 85, then sin, cos, tan
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Ariel G.
tysm! can you tell me the rule for cos and sin as well? like now I know that tan is either - or + 180, are sin and cos like that too? or are there a different method?04/11/21