Ashy A.

asked • 04/10/21

physics question

You load a 7.6g AAA battery into your new mini penlight flashlight. The spring at the bottom of the battery compartment has a k=89 and you compress it 2.0 cm as you screw on the cap. At camp you drop the flashlight and the top breaks off.

a. What is the velocity of the battery as it leaves the top of the spring? (assume no friction)

Answer: 2.1m/s.

b. How far above the top of the spring will the battery fly when it is released? (assume no air resistance) Answer: 0.24m.

1 Expert Answer

By:

Dr Gulshan S. answered • 04/11/21

Tutor
4.9 (52)

Physics Teaching is my EXPERTISE with assured improvement

About this tutor ›
About this tutor ›

Give units of k ?

Upvote • 1 Downvote
More
Report

Ashy A.

k = 89N/m
Report

04/11/21

Dr Gulshan S.

tutor
EPE = 1/2 Kx^2 = Kinetic energy = 1/2mv^2 V^2 = sqrt ( Kx^2/m)= 4.68 ( Plug in x in m , m in Kg , K in N/m) Gives V^2 = 4.68 Gives V= 2.16m/s Now Using Vi^2 = 2gH H = Vi^2 /2g = 4.68/(2*9.8) = 0.238 m = 0.24 m
Report

04/11/21

Dr Gulshan S.

tutor
Ask me if you have any question!
Report

04/12/21

Ashy A.

Thank you so much! this helped a lot :))
Report

04/13/21

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.