J.R. S. answered • 04/07/21
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
c). heat lost by iron = heat gained by water
heat lost by iron = q = mC∆T = (72.4 g)(0.449 J/gº)(100 - Tf)
heat gained by water = q = mC∆T = (100 g)(4.184 J/gº)(Tf - 10)
(72.4 g)(0.449 J/gº)(100 - Tf) = (100 g)(4.184 J/gº)(Tf - 10)
3251 - 32.5Tf = 418.4Tf - 4184
450.9Tf = 7435
Tf = 16.5º = final temperature
b). For water, q = mC∆T = (100 g)(4.184 J/gº)(6.5º) = 2720 J of heat gained by the water
a). For iron, q = mC∆T = (72.4 g)(0.449 J/gº)(83.5º) = 2714 J of heat lost by the iron
(note: the heat lost by iron should equal the heat gained by water. The fact they differ by 6 J may be a result of rounding in the calculations)
