2 bears and honey

Question

it takes a bear nine more days to eat a barrel of honey alone then it takes the bear and the second bear to eat the barrel of huney together it takes the first bear seven fewer days to eat a barrel of huney alone and it takes a second beat eat a barrel of huney alone how many days can the two bears eat a barrel of money together

Answer 1

B= 9+ T

B=G-7 = 9+T

G =T+16 where B= time for 1st bear along, G= time for 2nd bear alone and T = time when they eat together.

1/B + 1/G = 1/T

1(9+T) + 1/(T+16) = 1/T multiply by T(T+9)(T+16)

T(T+16) + T(T+9) = (T+9)(T+16)

T^2 +16T + T^2 + 9T = T^2 + 25T + 144

T^2 = 144

T = 12 days together

1st bear took 21 days alone

2nd bear took 28 days alone

1/21 + 1/28 = 1/12

multiply by 84

4 + 3 + 84/12 = 7