Calculate the horizontal component of the net force, in newtons, on the charge which lies at the lower left corner of the rectangle.

Question

Four point charges of equal magnitude Q = 55 nC are placed on the corners of a rectangle of sides D₁ = 21 cm and D₂ = 11 cm. The charges on the left side of the rectangle are positive while the charges on the right side of the rectangle are negative. Use a coordinate system where the positive y direction is up and the positive x direction is to the right.

I get 1.10 * 10^-3 as the answer but its wrong so please show your work so I understand where i went wrong!

Answer 1

F_1x=kq²(1/.21²+.21/(.11²+.21²)^1.5)=.00105 N