
Yefim S. answered 03/10/21
Math Tutor with Experience
Voltage drop for each is 24 V because of parallel connection
i1 = v/R1 = 24V/10 ohms = 2.4 A, i2 = v/R2 = 24V/15 0hms = 1.6 A; i3 = v/R3 = 24V/20 ohms = 1.2 A
Current through battery i = 2.4A + 1.6A+ 1.2A = 5.2 A
R = v/i = 24V/5.2A = 4.615 Ohms
E1 = v2/R1·t = 242/10·600 = 34560 J
E2 = v2/R2·t = 242/15·600 = 23040 J
E3 = v2/R3·t = 242/20·600 = 17280 J ·