Inactive Tutor answered 03/07/21
Tutor
New to Wyzant
Relation will be z=k/t k is constant.
30=k/11 so k will be 30*11= 330
equation is z=330/ t
now we can evaluate 6 for t
z=330/6 z= 55
Inactive Tutor answered 03/07/21
Relation will be z=k/t k is constant.
30=k/11 so k will be 30*11= 330
equation is z=330/ t
now we can evaluate 6 for t
z=330/6 z= 55
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