A non-uniform force is

Question

applied to a 1.00kg mass as it moves in the positive x-direction. Initially, the object has a speed of 5.00m/s when it moves through the origin.

a) What is the speed at x = 2?

b) What is the speed of the particle at x = 4?

The graph has a domain of [0,4] and its peak is at (2,6). The speed is on the x-axis. F in the y-axis. It is in the shape of a triangle, and its peak is at (2,6). It travels in a straight line.

Answer 1

first lets get the acceleration of the mass

M=5kg F= 1kg initial velocity = 5 m/sec

acceleration = 1*5 =5meters sec^2

Now how does that help now we use the distance equation

distance = 1/2at^2 + V*t

solve equation using 2 as the distance to get the time

then the velosoti at 2 =vint +at