Find the value of x from this equation:

Question

3^2x-2-17^x-2+66 = 0.

Answer 1

3^2x-2-17^x-2+66=0

3^2x-2-17^x-2=-66

log3^2x-2-log17^x-2=-log(66)

(2x-2)log3-(x-2)log17=-log(66)

2xlog3-2log3-xlog17+2log17=-log(66)

x(2log3-log17)=2log3-2log17-log(66)

x=[2log3-2log17-log(66)]/[2log3-log17]

x=12.04