Jon S. answered 02/11/21
Patient and Knowledgeable Math and English Tutor
mean = 520, standard deviation (SD) = 50
x = score
z = (x - mean)/SD
a) What proportion have a score between 420 and 620? a) _____________
P is probability. We transforms x to z using above formula.
P(420 < x < 620) = P( (420-520)/50 < z < (620-520)/50) = P(-2 < z < 2) = P(z < 2) - P(z < -2) = 0.9772 - 0.0228 = 0.9544
b) What proportion have a score between 520 and 620? b) ____________
P(520 < x < 620) = P( (520-520)/50 < z < (620-520)/50) = P(0 < z < 2) = P(z < 2) - P(z < 0) = 0.9772 - 0.5 = 0.4772
c) What proportion have a score between 470 and 620? c) _____________
P(470 < x < 620) = P( (470-520)/50 < z < (620-520)/50) = P(-1 < z < 2) = P(z < 2) - P(z < -1) = 0.9772 - 0.1587 = 0.8185
d) What proportion have a score below 420? d) ____________
P(x < 420) = P(z < (420-520)/50) = P(z < -2) = 0.0228
e) What proportion have a score between 420 and 820? e) ____________
P(420 < x < 820) = P( (420-520)/50 < z < (820-520)/50) = P(-2 < z < 6) = P(z < 6) - P(z < -2) = 1 - 0.0228 = 0.9772
f) What is the z-score of a child who has a test score of 570? f) _____________
z = (570 - 520)/50 = 1
g) What is the z-score of a child who has a test score of 600? g) _____________
z = (600 - 520)/50 = 1.6
h) What is the z-score of a child who has a test score of 463? h) ____________
z = (463-520)/50 = -1.14
i) A child who has an exam score at the 50th percentile has a score of i) _____________
50th percentile is the mean, so score is 520.
j) A child who has an exam score at the 16th percentile has a score of j) _____________
16th percentile corresponds to z-score of approximately -1
-1 = (x - 520)/50
-50 + 520 = x
470 = x