James C. answered • 02/06/21
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sin(-2x)cos(9x) = (1/2)[sin(-2x + 9x) + sin(-2x - 9x)]
=1/2[sin(7x) + sin(-11x)]
Zoe S.
asked • 02/06/21Express as a sum or difference. (Use the Product-to-Sum formulas.)
Express as a sum or difference. (Use the Product-to-Sum formulas.)
sin(-2x) cos 9x
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