In an experiment run at 22°C, a reading from the eudiometer of 46.78 mL corresponds to what true volume

Question

A student calibrated a eudiometer by first recording the mass of the empty eudiometer followed by filling the eudiometer to the 50.00 mL line with deionized water at 22°C and recorded the mass. The mass of water was 49.012 g.

Can you please show work? I know true volume is what we actually got rather than what we filled up. I know getting 49.012 instead of 50ml is about 2% error in measuring.

Answer 1

You aren't getting 49.012 ml, you are measuring grams. So...

Density of water at 22ºC = 0.997770 g/mL.

49.012 g x 1 ml/0.997770 g = 49.12 ml (1.76% )

A reading of 46.78 ml corresponds to a true volume of 45.96 ml

This can be determined in 1 of 2 ways:

1). 46.78 ml x 0.0176 = 0.82298 and then 46.76 ml - 0.82298 ml = 45.96 ml

2). 100% - 1.76% = 98.24% and then 98.24% x 46.78 ml = 45.96 ml