logbx = (logax)/(logab) b is the given base and a is the base to which we want to convert
To find the derivative of logbx, convert to base e (natural logs):
logbx = lnx/lnb
lnb is a constant, so 1/lnb can be factored out as a constant multiple when taking the derivative of the right hand side
We then have: (logbx)' = (1/lnb)(lnx)'
= (1/lnb)(1/x)
= 1/(xlnb)
For example, (log4x)' = 1/(xln4)