Help me with this please

Question

Write a static void method that will take accept an int array as a parameter and will count the number of times the numbers, 0-9, appear in the array, which can just be print statements

Answer 1

class DigitStats

{

private int A[];

private long freqTable[];

DigitStats( int a[])

{

//deep copies

int N = a.length;

A = new int[N];

for (int iLoop=0; iLoop<N; iLoop++)

{

A[iLoop]=a[iLoop];

}

//clears the frequencies

freqTable = new long[10];

for (int iLoop=0; iLoop<10; iLoop++)

{

freqTable[iLoop]=0;

}

}

void Set( int a[])

{

//deep copies

int N = a.length;

A = new int[N];

for (int iLoop=0; iLoop<N; iLoop++)

{

A[iLoop]=a[iLoop];

}

//clears the frequencies

freqTable = new long[10];

for (int iLoop=0; iLoop<10; iLoop++)

{

freqTable[iLoop]=0;

}

}

protected void CalculateFrequencies()

{

for (int iLoop=0; iLoop<A.length; iLoop++)

{

String iNumbuff = (new Integer(A[iLoop])).toString();

System.out.println(iNumbuff);

int nStrLen = iNumbuff.length();

for (int jLoop=0; jLoop<nStrLen; jLoop++)

{

char chDigit = iNumbuff.charAt(jLoop);

if ((chDigit>='0') && (chDigit<='9'))

{

freqTable[chDigit-48]++;

}

}

}

}

public long[] GetFreq()

{

long longFreqTableReturn[] = new long[10];

CalculateFrequencies();

for (int iLoop=0; iLoop<10; iLoop++)

{

longFreqTableReturn[iLoop] = freqTable[iLoop];

}

return(longFreqTableReturn);

}

public static void main(String args[])

{

int iNums[] = { 1234,2345,3456,4567,5678,6789,7890,8901,9012};

DigitStats digitStats = new DigitStats(iNums);

long freqTable[] = digitStats.GetFreq();

System.out.println("----------------------------------------");

System.out.println(" DIGIT FREQ ");

System.out.println("-----------------------------------------");

for (int iLoop=0; iLoop<10; iLoop++)

{

System.out.println(" " + iLoop + " " + freqTable[iLoop]);

}

}

public void Clear()

{

A=null;

freqTable=null;

}

}

Answer 2

In this static void method, you can create a new array of ints with a length of 10. Let's call that array counter. Each index of the array will represent the number of times each number, 0-9, has been found.

Use a for loop to iterate through each index of the parameter array, and increment the appropriate index of counter. For instance, if you encounter a 5 in the parameter array, increase counter[5] by 1. If you encounter a 1, increase counter[1] by 1.

Once you've gone through the entire parameter array in this fashion, you'll have essentially counted the number of occurrences of each integer; the number of occurrences will be held in counter.

Lastly, print out the value of each index of counter!