Find the inverse of the function: h(x)= -2/(x-3) - 1

Answer 1

h(x)= -2/(x-3) - 1

Y = -2/(X-3) -1

Interchanging X and Y

X = -2/( Y -3 ) -1 =( -2 - Y +3 ) /( Y -3) = ( 1 - Y) /( Y-3)

Inverse Function is (3X +1)/(X +1)

Answer 2

h(x) = -2(x - 3) -1 Assuming the -1 is not in the denominator

x = -2(h'(x) - 3) -1

x + 1 = -2(h'(x) - 3)

(x + 1) / 2 = h'(x) - 3

[(x + 1) / 2] + 3 = h'(x)