
William W. answered 01/17/21
Experienced Tutor and Retired Engineer
g(altitude) = g(sea level)[re/(re + h)]2
g(sea level) = 9.80665 m/s2
re (mean) = 6371.009 km = 6371009 m
g(altitude) = 9.80665[6371009/(6371009 + 38000)]2
g(altitude) = 9.80665[6371009/6409009]2
g(altitude) = 9.80665[0.99407]2
g(altitude) = 9.80665(0.988177)
g(altitude) = 9.6907 m/s2
W = mg(altitude)
W = (71)(9.6907) = 688 N = 690 N
Strength of the Earth's gravity field where he jumped: 9.6907 N/kg
Weight as a ratio of weight on the Earth's surface: 0.988177 = 98.8%
In case you were wondering about the equation I used initially:
Newton's Universal Law of Gravitation is F = GmM/re2 where m is the mass of some random object on earth and M is the mass of the earth, G is the Universal Gravitational Constant and re is the radius of the earth.
But we also know (Newton's 2nd Law) that F = ma so:
ma = GmM/re2 and, since "m" is on both sides, it cancels out and we can change the acceleration to "g", the acceleration of gravity. So we have:
g = GM/re2 and this is the "g" at a distance from the center of the earth of "re" (or at sea level) so it would be better to say:
g(sea level) = GM/re2
We can manipulate this equation by multiplying both sides by re2 to get:
(re2)g(sea level) = GM
Then we can repeat this for a distance of re plus h (an altitude of "h") to get:
(re + h)2g(altitude) = GM
Since both equations equal "GM", we can set them equal to each other:
(re2)g(sea level) = (re + h)2g(altitude)
Then we can solve for g(altitude) :
g(altitude) = g(sea level)[re2/(re + h)2] or
g(altitude) = g(sea level)[re/(re + h)]2

William W.
I edited my answer to show the derivation of the equation I used.01/18/21
Ashy A.
but why would you square the r/r+h in the first place?01/18/21