
Bradford T. answered 01/14/21
Retired Engineer / Upper level math instructor
f(x) = x2+15x+50 = 0 (ax2+bx+c)
Factors of 50 are ±(1,2,5,10,25)
f(-5) = 25 - 75 + 50 = 0
f(-10) = 100 - 150 + 50 =0
So -5 and -10 are zeroes
(x+5)(x+10) --> x = -5, -10
Another way to factor ax2+bx+c is to pick which of the factors of c add up to ±b and multiply together to become c.