Find three consecutive odd integers such that the sum of 7 times the smallest and twice the largest is -91. please help i have to make legends and set up an equation

Answer 1

S=x-2 = smallest number

M=x = middle number

L=x+2= largest number

7S+2L =-91

7(x-2)+2(x+2) =-91

7x-14 +2x+4 =-91

9x =-91 +14-4 =-81

x =-81/9 =-9

x-2 = -11

x+2 = -7

the 3 numbers are -11, -9, and -7. -11 is the smallest, -7 is the largest

7 times smallest = -77

2 times largest = -14

-77-14 = -91