what is the magnitude and direction of the velocity of the baseball after it is hit?

Question

A baseball pitcher throws a 0.25 kg ball at a speed of 50 m/s to the east. If the batter strikes the ball with a force of 175 N to the west for a duration of 0.15 seconds, what is the magnitude and direction of the velocity of the baseball after it is hit?

Answer 1

The impulse [Fxt] equals the change in momentum [mv_f - mv_i] ; solve for v_f with East + & West −

v_f = [F x t] + mv_i ÷ m = [-175 x 0.15] + 0.25 x 50 = -13.75 m/s [West]