Patrick B. answered 12/23/20
Math and computer tutor/teacher
First of all , the function can be
slightly simplified:
S(t) = 4 + 31 * 4 ln(t+1)
= 4 + 124*ln(t+1)
part A:
Beginning typist --> t =0
S(0) = 4 + 124 ln(0+1)
= 4 + 124 ln 1
= 4 + 124*0
= 4 + 0
= 4
part B:
t=3 months
S(3) = 4 + 124*ln(3+1)
= 4 + 124*ln 4
= 176
part c:
65 = 4 + 124*ln (t+1)
61 = 124 ln(t+1)
61/124 = ln(t+1)
exp(61/124) = t+1
exp(61/124)-1 = t
1.63... - 1 = t
0.63... months
about 2+1/2 weeks