
Mark M. answered 12/22/20
Tutor
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(278)
Mathematics Teacher - NCLB Highly Qualified
cos θ = (x - 1) / 3
sin θ = (y - 1) / 5
sin2 θ + cos2 θ = 1
[(x - 1) / 3]2 + [(y - 2) / 5]2 = 1

Titus Jr I.
asked 12/22/20x=1+3cos(theta)
y=1+5sin(theta)
Mark M. answered 12/22/20
Mathematics Teacher - NCLB Highly Qualified
cos θ = (x - 1) / 3
sin θ = (y - 1) / 5
sin2 θ + cos2 θ = 1
[(x - 1) / 3]2 + [(y - 2) / 5]2 = 1
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Nazlee R.
12/22/20