find three additional polar representations of the point, using -2pi<theta<2pi

Question

a.

b.  

Answer 1

(- 6, 2π/3) = (6, 2π/3 + π) = (6, 5π/3);

(- 6, 2π/3) = (6, 2π/3 - π) = (6, - π/3)

(- 6, 2π/3) = (-- 6, 2π/3 - 2π) = (- 6, - 4π/3),

(- 3, 11π/6) = (3, 11π/6 - π) = (3, 5π/6)

(- 3, 11π/6) = (- 3, 11π/6 - 2π) = (- 3, - π/6)

(- 3, 11π/6) = (3, 11π/6 - 3π) = (3, - 7π/6)