
Anthony T. answered 11/30/20
Patient Science Tutor
Hi, Emma
I made a mistake in the linear interpolation the last time I did this problem for you. I hope this time is better.
To find the mass of water at a given temperature and relative humidity, you have to know the mass of water vapor in a cubic meter of air when the air is saturated at the temperature.
First calculate the volume of the room in m3. Multiply the 3 dimensions together. Volume = 15*8*5 = 600 m3.
I found data for the vapor density of saturated water vapor at 20 C and 30 C which is 0.017 and 0.03 kg/m3.
Linearly interpolate to get the value at 25 C to get 0.0235 kg/m3. This is an approximation as the curve is not linear.
The total mass of water in the room at saturation is 600 m3 x 0.0235 kg/m3 = 14.1 kg. As the relative humidity is 57%, the actual mass of water vapor is 0.57 x 141 kg = 8 kg approximately.
Please comment if this is a better result. Thanks.