Physics question

Question

A box takes 350 N to start moving when the coefficient of static friction is 0.35. What is the mass of the box? m = 101.94 kg

Idk how to do this prob

Answer 1

The force needed to get the box moving must just cancel the static friction force:

F = µ_smg = 0.35•m•9.81 = 350 ---> m = 350 / (0.35•9.81) = 101.937 kg

Again, with units shown, and using 1 N = 1 kg•m/s²:

0.35•m•9.81(m/s²) = 350 N

solving for m:

m = 350 N / (0.35•9.81 m/s²) = (350 kg•m/s²) / (3.434 m/s² ) = 101.937 kg

Answer 2

Well force needed to get the box moving = force of static friction

Force of static friction = coefficient x normal force = 0.35 x mass x g = 0.35 x m x 9.81

So 350 = 0.35 x 9.81 x m

You can solve this for m