Frank A. answered • 11/27/20
Tutor
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Math is the language of science; I am very fluent in it.
In the drawing, the box is being pulled up the ramp at a constant velocity. The ramp's angle is 30 degrees.
A. How does the force applied parallel to the ramp compare to the force of friction?
When velocity is constant, net force is zero. Force up the incline is exactly equal to the friction force which is acting down the incline.
B. If the force parallel is 30 and the mass of the box is 2Kg, what is the coefficient of friction?
μ (coefficient of friction) = Friction / Normal
= 30/2•9.81•cos30 = 1.76
Mr, A
