Inactive Tutor answered 11/23/20
(a) Net force will be force due to gravity down the ramp = mg sin θ, where θ is the angle of elevation of the ramp.
(b) Use F=ma. Use F from part (a).
(c) Use v2 = u2 + 2as. u = 7, s = 3.12, a you get from (b)
Ashy A.
asked 11/23/20An 87 kg skier enters the bottom of a 3.12 m Ski Jump at 7.0 m/s. Assuming no friction on the jump:
a) What is the net force on the skier while going up the 38° Jump? Ans: -525. N
b) What is the skier’s acceleration on the jump? Ans: -6.03 m/s^2
c) What is their speed at the top of the jump if there was no friction? Ans: 3.37m/s
idk how to do this?
Inactive Tutor answered 11/23/20
(a) Net force will be force due to gravity down the ramp = mg sin θ, where θ is the angle of elevation of the ramp.
(b) Use F=ma. Use F from part (a).
(c) Use v2 = u2 + 2as. u = 7, s = 3.12, a you get from (b)
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