Robert Z. answered 10/27/20
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The volume of the balloon material itself is insignificant, so we will say that the volume of the balloon and the helium inside it is 0.1 m3. Let b be the mass of the balloon. Then the mass of the balloon inflated with 0.1 m3 of helium is b + 0.01786 kg. The critical value of b is the mass that brings this sum up to the mass of the same volume of air, which is 0.1275 kg.
So, b = 0.1275 kg - 0.0179 kg = 0.1096 kg