Don't beat yourself up!
You got the right answer.
sin(n) does not approach a limit as n increases; therefore, the sum diverges....end of story!
Ashley P.
asked 10/18/20Hello, I have a question related to the convergence or divergence of an infinite series.
Question : Test the convergence/divergence of the series sin(n), using a suitable test.
My thoughts : So for this one, I immediately thought of applying the test for divergence(which states if the limit of the nth term of the series, as n->infinity, is not equal to zero, then the series diverges)
Hence, we need to find lim n->infinity (sin(n)).
But what is the value of the limit, lim n->infinity (sin(n))?
Does that exists or is it indeterminate?
We know that the behaviour of the graph of sin(n) is periodic.
So is sigma(sin(n)) divergent? What is the reason?
Or is there any other suitable test for testing this series for convergence or divergence?
Thank you
Don't beat yourself up!
You got the right answer.
sin(n) does not approach a limit as n increases; therefore, the sum diverges....end of story!
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Ashley P.
So we can simply say the limit doea not exist right?10/18/20