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Soshi K.

asked • 10/15/20

1-D Kinematics of Particles

Particle 𝐴, which is initially at rest, wants to meet Particle 𝐵, however they are 𝑋𝑌𝑍 ft away from one another. The motion of particle 𝐴 heading toward 𝐵 is defined by the relation: 𝑠 = 1/𝑎2 where 𝑠 and 𝑎 are expressed in ft and ft s 2 , respectively. On the other hand, Particle 𝐵 travels toward 𝐴 with an initial velocity of 0.25 ft s that increases at the rate of 0.50 ft s 2 . With the motion of each particle described above, determine when and where they will meet each other in reference to Particle 𝐴’s initial position.

Petros H.

Please, try to present the problem more understandable. For example, is XYZ a 3D distance, or it is just your symbol? Next, the relation S=a^-2 , maybe is S(t)=(a^-2)t^2 , since without time the formula cannot describe a motion. If so, the both motions are accelerated: for A S(t)=(a^-2)t^2, for B V(t)= 0.25 +0.5t; then for B after integration S(t)=0.25t+0.25t^2. Now, you will have three unknowns (t, S for A, and S for B) and three equations (Sa, Sb, and (Sa+Sb)=XYZ)


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