i've spent hours trying to figure this out but i can't

Question

1) A tiger leaps horizontally from a 6.5m height rock with a speed of 3.5m/s. How far from the base of the rock will the tiger land?

 The tiger will land 4 meters away from the rock

2) A projectile is shot from the edge of a cliff 125m above ground level with an initial speed of 65 m/s at an angle of 00 above the horizontal. 

a) Determine the time taken by the projectile to hit ground level.

It will take the projectile 18.46 seconds to hit the ground

b) Determine the distance the projectile travels measured from the base of the cliff to the landing point.

Answer 1

The tiger is moving horizontally so the initial velocity in the x-direction is 3.5 m/s. There is nothing to slow that speed so the velocity in the x-direction at any time will remain 3.5 m/s. Considering the y-direction though, the tiger has an initial velocity (y-direction only) of zero and accelerates downward because of the acceleration of gravity. We can use x = v_it + 1/2at² to find the time it takes. Since v_i = zero, and "a" = 9.81 m/s², we can say 6.5 = 1/2(9.81)t²

t² = 1.32518

t = √1.32518 = 1.15116 seconds

During that time, in the x-direction the tiger has continued traveling at 3.5 m/s so it would have traveled (3.5)(1.15116) or 4.0 meters.

The other problem uses the same technique.