Nawaf E.
asked • 10/08/20Please answer the Question in description.
Your long distance telephone provider offers two plans. Plan A has a monthly fee of $15 and $0.25 per minute. Plan B has a monthly fee of $20 and $0.05 per minute. Write and solve an equation to find the number of minutes that you must talk to have the same cost for each of the plans.
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1 Expert Answer
Robin S. answered • 10/08/20
Tutor
5.0
(678)
Retired Mathematics Certified (Elementary and 6-12 Math) Teacher
This is a system of equations.
The first equation for A is y = .25x + 15 (the rate per call + flat fee)
THe second equation B is y = .05x + 20 (as above)
Since y equals both of those, you could use substitution to set them equal to each other.
.25x + 15 = .05x + 20 Shift x and its coefficient to the left by subtraction and the constant value to the right by subtraction also.
.25x + 15 = .05x + 20
-.05x -.05x
.20x + 15 = 20
-15 -15
.20x = 5 Divide 5 by .20 and you get x = 25 So at 25 minutes both plans are the same.
Nawaf E.
Thank you so much
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10/08/20
Nawaf E.
Can you do one more question for me please? You purchase a desk for 60% of the original price p. This price is $32 less than the original price. Write and solve an equation to find the original price of the desk.
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10/08/20
Robin S.
Sure
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10/08/20
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Robin S.
This is a system of equations. The first equation for A is y = .25x + 15 (the rate per call + flat fee) THe second equation B is y = .05x + 20 (as above) Since y equals both of those, you could use substitution to set them equal to each other. .25x + 15 = .05x + 20 Shift x and its coefficient to the left by subtraction and the constant value to the right by subtraction also. .25x + 15 = .05x + 20 -.05x -.05x .20x + 15 = 20 -15 -15 .20x = 5 Divide 5 by .20 and you get x = 25 So at 25 minutes both plans are the same.10/08/20