The given data shows a range from 93.5oC to 24.9oC, which has a Δ of 68.6oC. That difference occurred over a period of 40 minutes, which yields an average of -1.7oC per minute.
1. A very good generalization can be made as follows:
When plotted on a graph, the data yield a straight line from 93.5oC to 24.9oC with a negative slope. Thus, we can determine the formula for this straight line to be Y = -mX +93.5.
When we compose of table of X values from 0 to 40, the results match well with the observations, and yields an average decline of 8.6oC per 5 minutes..
2. To use the linear regression method (least squares method):
we consider the first measurement as time 1, extend the line to the y axis, where we find the intercept is 97.1. The mean value is 61.7.
With this information, we can compute the data points by x = X - Xa, where Xa is the mean value for X, and Y = Y -Ya, where Ya is the mean value for Y, and then compute values using the formula: y = (∑xy/∑x2)x
Regression line equation: Y= -1.66X + 97.1, and yields an average decline of 8.3oC per 5 minutes.
By the way, the most influential measurement was #3 (70.2oC at 18 minutes). In practice, a second set of measurements would be in order.
By the way, the most influential measurement was #3 (70.2oC at 18 minutes). In practice, a second set of measurements would be in order.