Hello, Rachel,
Dylan is spending at a constant rate of 9 quarters per half hour. I'll make this a rate of 18 per hour, for convenience. Since the rate is constant, his spending behavior can be expressed as a linear equation of the form
y = mx + b
where y is the number of quarters, m is the slope (in this case the rate of spending), x is time (I'll make it 1 hour increments), and b is the y intercept at x = 0. Since Dylan's quarter stash drops with time, the slope here would be -18 quarters/hour.
y = -18x + b
At x = 0, the time Dylan arrived at the machine with a big grin, he had b quarters since y = -18*0 + b, or y = b.
Say that Dylan came with 100 quarters, for example. That 100 would be the point at which the line crosses the y axis at t = 0, or (0,100). So Dylan's initial quarter count is the y intercept.
Bob