Omar L. answered • 09/18/20

Experienced Engineer Specializing in Tutoring Maths and Sciences

Hi Bee,

Let d1, d2, and d3, denote the distance over the 3 legs of the trip:

d1: P to B, d2: B to J, d3: J to P.

For the first trip, he travels from P (100, 40) to B (40, 80). That means he traveled 40-100=-60 in the x direction and 80-40=40 in the y direction. Using the Pythagorean theorem, he has traveled:

d1 = sqrt(Δx^{2}+Δy^{2}) = sqrt((-60)^{2}+(40)^{2}) = 72.111

In the same way,

d2 = sqrt(Δx^{2}+Δy^{2}) = sqrt((90)^{2}+(25)^{2}) = 93.408

d3 = sqrt(Δx^{2}+Δy^{2}) = sqrt((-30)^{2}+(-65)^{2}) = 71.589

Adding these all up for the total trip,

d = d1+d2+d3 = 237.11

I hope that helps.

BR,

Omar

Bee M.

Thank you so much!09/20/20